Optimal. Leaf size=161 \[ -\frac {3 \text {Int}\left (\frac {1}{x^4 \tan ^{-1}(a x)^2},x\right )}{2 a c^2}+\frac {a \text {Int}\left (\frac {1}{x^2 \tan ^{-1}(a x)^2},x\right )}{2 c^2}-\frac {a^2 \text {Si}\left (2 \tan ^{-1}(a x)\right )}{c^2}-\frac {a^2 \left (1-a^2 x^2\right )}{2 c^2 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}-\frac {a^3 x}{2 c^2 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)^2}-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+\frac {a}{2 c^2 x \tan ^{-1}(a x)^2} \]
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Rubi [A] time = 0.41, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x^3 \left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^3} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {1}{x^3 \left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^3} \, dx &=-\left (a^2 \int \frac {1}{x \left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^3} \, dx\right )+\frac {\int \frac {1}{x^3 \left (c+a^2 c x^2\right ) \tan ^{-1}(a x)^3} \, dx}{c}\\ &=-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+a^4 \int \frac {x}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^3} \, dx-\frac {3 \int \frac {1}{x^4 \tan ^{-1}(a x)^2} \, dx}{2 a c^2}-\frac {a^2 \int \frac {1}{x \left (c+a^2 c x^2\right ) \tan ^{-1}(a x)^3} \, dx}{c}\\ &=-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+\frac {a}{2 c^2 x \tan ^{-1}(a x)^2}-\frac {a^3 x}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}-\frac {a^2 \left (1-a^2 x^2\right )}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\left (2 a^4\right ) \int \frac {x}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)} \, dx-\frac {3 \int \frac {1}{x^4 \tan ^{-1}(a x)^2} \, dx}{2 a c^2}+\frac {a \int \frac {1}{x^2 \tan ^{-1}(a x)^2} \, dx}{2 c^2}\\ &=-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+\frac {a}{2 c^2 x \tan ^{-1}(a x)^2}-\frac {a^3 x}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}-\frac {a^2 \left (1-a^2 x^2\right )}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {3 \int \frac {1}{x^4 \tan ^{-1}(a x)^2} \, dx}{2 a c^2}+\frac {a \int \frac {1}{x^2 \tan ^{-1}(a x)^2} \, dx}{2 c^2}-\frac {\left (2 a^2\right ) \operatorname {Subst}\left (\int \frac {\cos (x) \sin (x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c^2}\\ &=-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+\frac {a}{2 c^2 x \tan ^{-1}(a x)^2}-\frac {a^3 x}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}-\frac {a^2 \left (1-a^2 x^2\right )}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {3 \int \frac {1}{x^4 \tan ^{-1}(a x)^2} \, dx}{2 a c^2}+\frac {a \int \frac {1}{x^2 \tan ^{-1}(a x)^2} \, dx}{2 c^2}-\frac {\left (2 a^2\right ) \operatorname {Subst}\left (\int \frac {\sin (2 x)}{2 x} \, dx,x,\tan ^{-1}(a x)\right )}{c^2}\\ &=-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+\frac {a}{2 c^2 x \tan ^{-1}(a x)^2}-\frac {a^3 x}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}-\frac {a^2 \left (1-a^2 x^2\right )}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {3 \int \frac {1}{x^4 \tan ^{-1}(a x)^2} \, dx}{2 a c^2}+\frac {a \int \frac {1}{x^2 \tan ^{-1}(a x)^2} \, dx}{2 c^2}-\frac {a^2 \operatorname {Subst}\left (\int \frac {\sin (2 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c^2}\\ &=-\frac {1}{2 a c^2 x^3 \tan ^{-1}(a x)^2}+\frac {a}{2 c^2 x \tan ^{-1}(a x)^2}-\frac {a^3 x}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}-\frac {a^2 \left (1-a^2 x^2\right )}{2 c^2 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac {a^2 \text {Si}\left (2 \tan ^{-1}(a x)\right )}{c^2}-\frac {3 \int \frac {1}{x^4 \tan ^{-1}(a x)^2} \, dx}{2 a c^2}+\frac {a \int \frac {1}{x^2 \tan ^{-1}(a x)^2} \, dx}{2 c^2}\\ \end {align*}
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Mathematica [A] time = 2.30, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^3 \left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^3} \, dx \]
Verification is Not applicable to the result.
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fricas [A] time = 0.59, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{{\left (a^{4} c^{2} x^{7} + 2 \, a^{2} c^{2} x^{5} + c^{2} x^{3}\right )} \arctan \left (a x\right )^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 2.69, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{3} \left (a^{2} c \,x^{2}+c \right )^{2} \arctan \left (a x \right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {4 \, {\left (a^{4} c^{2} x^{6} + a^{2} c^{2} x^{4}\right )} \arctan \left (a x\right )^{2} \int \frac {5 \, a^{4} x^{4} + 7 \, a^{2} x^{2} + 3}{{\left (a^{6} c^{2} x^{9} + 2 \, a^{4} c^{2} x^{7} + a^{2} c^{2} x^{5}\right )} \arctan \left (a x\right )}\,{d x} - a x + {\left (5 \, a^{2} x^{2} + 3\right )} \arctan \left (a x\right )}{2 \, {\left (a^{4} c^{2} x^{6} + a^{2} c^{2} x^{4}\right )} \arctan \left (a x\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [A] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{x^3\,{\mathrm {atan}\left (a\,x\right )}^3\,{\left (c\,a^2\,x^2+c\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {1}{a^{4} x^{7} \operatorname {atan}^{3}{\left (a x \right )} + 2 a^{2} x^{5} \operatorname {atan}^{3}{\left (a x \right )} + x^{3} \operatorname {atan}^{3}{\left (a x \right )}}\, dx}{c^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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